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NUMBERS

In this problem, you have to find the last three digits before the decimal point for the number (3 + √5) **$^n$** . For example, when **n** = 5, (3 + √5)$^5$ = 3935.73982... The answer is 935. For **n** = 2, (3 + √5)$^2$ = 27.4164079... The answer is 027. --- ###Input The first line of input gives the number of cases, **T**. **T** test cases follow, each on a separate line. Each test case con

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solution.cppC++17

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