The Numbers, Mason !

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Mason is yet again in danger. Consider an N digit number A. let the new number formed by reversing the digits of A be called B . Mason has to tell that how many N digit numbers A exist such that A + B = 10N - 1 ? Note: A should not have any leading zeroes ! Quick. Help. over and out. Input First line will contain the number of test cases T , then T lines follow each containing an int

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solution.cppC++17

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