SubInversing

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You initially start with a binary string S0 which is of length N and has all 0s. You are then given U updates, which keep transforming the string. The i-th update transforms the string Si-1 into Si, and hence after all the U updates you will be left with SU. A single update is of the form (Li, Ri), which means that all the 1s in the range [Li, Ri] (both end points included) should be changed int

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solution.cppC++17

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