Nesting a Bunch of Brackets

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In this problem we consider expressions containing brackets that are properly nested. These expressions are obtained by juxtaposition of properly netsted expressions in a pair of matching brackets, the left one an opening and the right one a closing bracket. ( a + $ ( b = ) ( a ) ) is properly nested ( a + $ ) b = ) ( a ( ) is not. In this problem we have several pairs of brackets, so we have t

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solution.cppC++17

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